北师大版八年级下册第1章三角形的证明单元检测卷A一

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1、北师大版八年级下册第1章 三角形的证明2014年单元检测卷A(一)一、选择题(每小题4分,共48分)1等腰三角形的一个角是80,则它顶角的度数是()A80B80或20C80或50D20显示解析2下列命题的逆命题是真命题的是()A如果a0,b0,则a+b0B直角都相等C两直线平行,同位角相等D若a=6,则|a|=|b|显示解析3ABC中,A:B:C=1:2:3,最小边BC=4cm,最长边AB的长是()A5cmB6cmC7cmD8cm显示解析4如图,已知AE=CF,AFD=CEB,那么添加下列一个条件后,仍无法判定ADFCBE的是()AA=CBAD=CBCBE=DFDADBC显示解析5如图,在AB

2、C中,B=30,BC的垂直平分线交AB于E,垂足为D若ED=5,则CE的长为()A10B8C5D2.5显示解析6如图,D为ABC内一点,CD平分ACB,BECD,垂足为D,交AC于点E,A=ABE若AC=5,BC=3,则BD的长为()A2.5B1.5C2D1显示解析7如图,AB=AC,BEAC于点E,CFAB于点F,BE、CF相交于点D,则ABEACF;BDFCDE;点D在BAC的平分线上以上结论正确的是()ABCD显示解析8如图所示,ABBC,DCBC,E是BC上一点,BAE=DEC=60,AB=3,CE=4,则AD等于()A10B12C24D48显示解析9如图所示,在ABC中,AB=AC,

3、D、E是ABC内两点,AD平分BACEBC=E=60,若BE=6,DE=2,则BC的长度是()A6B8C9D10显示解析10如图,在ABC中,C=90,B=30,以A为圆心,任意长为半径画弧分别交AB、AC于点M和N,再分别以M、N为圆心,大于12MN的长为半径画弧,两弧交于点P,连结AP并延长交BC于点D,则下列说法中正确的个数是()AD是BAC的平分线;ADC=60;点D在AB的中垂线上;SDAC:SABC=1:3A1B2C3D4显示解析11如图,在平面直角坐标系xOy中,A(0,2),B(0,6),动点C在直线y=x上若以A、B、C三点为顶点的三角形是等腰三角形,则点C的个数是()A2B

4、3C4D5显示解析12如图,在等腰RtABC中,C=90,AC=8,F是AB边上的中点,点D,E分别在AC,BC边上运动,且保持AD=CE连接DE,DF,EF在此运动变化的过程中,下列结论:DFE是等腰直角三角形;四边形CDFE不可能为正方形,DE长度的最小值为4;四边形CDFE的面积保持不变;CDE面积的最大值为8其中正确的结论是()ABCD显示解析二、填空题(每小题4分,共24分)13用反证法证明命题“三角形中必有一个内角小于或等于60”时,首先应假设这个三角形中显示解析14若(a-1)2+|b-2|=0,则以a、b为边长的等腰三角形的周长为显示解析15如图,在RtABC中,ABC=90,

5、DE是AC的垂直平分线,交AC于点D,交BC于点E,BAE=20,则C=显示解析16如图,在ABC中,BI、CI分别平分ABC、ACF,DE过点I,且DEBCBD=8cm,CE=5cm,则DE等于显示解析17如图,圆柱形容器中,高为1.2m,底面周长为1m,在容器内壁离容器底部0.3m的点B处有一蚊子,此时一只壁虎正好在容器外壁,离容器上沿0.3m与蚊子相对的点A处,则壁虎捕捉蚊子的最短距离为m(容器厚度忽略不计)显示解析18如图,在RtABC中,C=90,B=60,点D是BC边上的点,CD=1,将ABC沿直线AD翻折,使点C落在AB边上的点E处,若点P是直线AD上的动点,则PEB的周长的最小

6、值是显示解析三、解答题(每小题7分,共14分)19如图,C是AB的中点,AD=BE,CD=CE求证:A=B显示解析20如图,两条公路OA和OB相交于O点,在AOB的内部有工厂C和D,现要修建一个货站P,使货站P到两条公路OA、OB的距离相等,且到两工厂C、D的距离相等,用尺规作出货站P的位置(要求:不写作法,保留作图痕迹,写出结论)显示解析四、解答题(每小题10分,共40分)21在四边形ABCD中,ABCD,D=90,DCA=30,CA平分DCB,AD=4cm,求AB的长度?显示解析22如图,在ABC中,C=90,AD平分CAB,交CB于点D,过点D作DEAB于点E(1)求证:ACDAED;(

7、2)若B=30,CD=1,求BD的长显示解析23如图,把一个直角三角形ACB(ACB=90)绕着顶点B顺时针旋转60,使得点C旋转到AB边上的一点D,点A旋转到点E的位置F,G分别是BD,BE上的点,BF=BG,延长CF与DG交于点H(1)求证:CF=DG;(2)求出FHG的度数显示解析24已知:如图,ABC中,ABC=45,DH垂直平分BC交AB于点D,BE平分ABC,且BEAC于E,与CD相交于点F(1)求证:BF=AC;(2)求证:CE12BF显示解析五、解答题(每小题12分.共24分)25如图,在ABC中,D是BC是中点,过点D的直线GF交AC于点F,交AC的平行线BG于点G,DEDF

8、交AB于点E,连接EG、EF(1)求证:BG=CF;(2)求证:EG=EF;(3)请你判断BE+CF与EF的大小关系,并证明你的结论显示解析26ABC中,AB=AC,点D为射线BC上一个动点(不与B、C重合),以AD为一边向AD的左侧作ADE,使AD=AE,DAE=BAC,过点E作BC的平行线,交直线AB于点F,连接BE(1)如图1,若BAC=DAE=60,则BEF是三角形;(2)若BAC=DAE60如图2,当点D在线段BC上移动,判断BEF的形状并证明;当点D在线段BC的延长线上移动,BEF是什么三角形?请直接写出结论并画出相应的图形kA1DkaGtgKQcWA3P tGZ7R4I30kA1

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11、A1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2C

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14、FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv

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20、eaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2C

21、HhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32

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24、2tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtg

25、KQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CH

26、hI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGshLs50cLmTWN60eo8Wgqv7XAv2OHUm32WGeaUwYDIAWGMeR4I30kA1DkaGhn3XtKknBYCUDxqA7FHYi2CHhI92tgKQcWA3PtGZ7R4I30kA1DkaGtgKQcWA3PtGZ7R4I30

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