华科周纯杰版c语言答案

《华科周纯杰版c语言答案》由会员分享，可在线阅读，更多相关《华科周纯杰版c语言答案（49页珍藏版）》请在装配图网上搜索。

1、第三章 程序和流程控制 1.输入两个整数，输出较大者。 #includevoid main()int a,b; int max=0;printf(Please input two numbers:);scanf(%d%d,&a,&b);if(a=b) max=b;else max=a;printf(The larger number is %dn,max);2.有3个整数a，b，c，由键盘输入，输出其中最大的数。#includevoid main()int a,b,c,max;printf(Please input three numbers:);scanf(%d%d%d,&a,&b,&c);

2、if(ab) if(ac) max=a; else max=c;elseif(bc) max=b; else max=c;printf(The largest number is %dn,temp);3.从1累加到100，用while语句。#include#define N 100void main()int i=1,sum=0;while(i=N) sum+=i; i+;printf(sum:%dn,sum);4.已知a110，a2 3，an3an-1 an-2 ，求 a 的前十项。#include#define N 10void main()int a20=10,-3;int i=0,m=

3、0;for(i=2;iN;i+) ai=3*ai-1+ai-2; m=N;printf(The %d numbers are:n,m);for(i=0;iN;i+) printf(a%d=%dn,i+1,ai); 5.输入一个自然数，判断它是奇数还是偶数。 #includevoid main()int a, temp;printf(Please input a numbers:n);scanf(%d,&a);temp=a%2;if(temp=0) printf(The number %d is an even!n,a);else printf(The number %d is an odd n

4、umber!n,a);6.已知a1 8，an an-1 bn ，b1 1，bn bn-1 3，求 a 前10项之和。 #include#define N 10void main()int aN=8,bN=1,i,sum=0;for(i=1;iN;i+) bi=bi-1+3; for(i=1;iN;i+) ai=ai-1+bi; for(i=0;iN;i+) sum+=ai; printf(The sum is:%dn,sum);7.有一个函数 写一程序，输入x，输出Y的值。 #includevoid main()float x,y;printf(Please input a float num

5、ber x=:);scanf(%f,&x);printf(x=%f,x);if(x=10) y=3*x-11; else y=2*x-1; printf(The value of y is:%.3fn,y);8.给一个不多于5位的的正整数，要求：求出它是几位数，分别打印出每一位数字，最后按照逆序打印各位数字，例如原数为321，应输出为123。 #include#define N 99999#define M 5void main()int i,j,k,m,bM;long int a,temp;printf(Please input a number:n);scanf(%ld,&a);if(aN

6、) printf(Error in input data!n);else temp=a; for(i=0;temp!=0;i+) temp=temp/10; m=i; printf(The number a=%ld have %d single numbersn,a,m); temp=a; for(j=0;j=0;j-) printf(%dt,bj); printf(n); printf(The inverted numbers are:n); for(j=0;jm;j+) printf(%d,bj); printf(n);9编写一猜数游戏程序，随机产生某个整数，从键盘反复输入整数进行猜数，当

7、未猜中时，提示输入过大或过小.猜中时，指出猜的次数.最多允许猜20次. #include#include#include#define N 10void main() int a,b,i; randomize(); a=random(N); printf(Please input number you guess:n); for(i=0;ia) printf(Your number is too big!n); else printf(Your number is too small!n); printf(n); 10.计算1999中能被3整除，且至少有一位数字是5的所有整数。 #includ

8、e#define N 999void main() int i,b,c,d; printf(The numbers are:n); for(i=1;i=N;i+) if(i%3) b=i/100; c=(i-100*b)/10; d=i%10; if(b=5|c=5|d=5) printf(%dt,i); 11.输入两个整数，求它们的最大公约数和最小公倍数。#include stdio.hvoid main()int a,b,c,d;int comYueShu;int comBeishu;printf(please input two number!);scanf(%d %d,&a,&b);c

9、=a;d=b;int r;/求公约数算法while(c%d)r=c%d;c=d;d=r;comYueShu=d;comBeishu=a*b/comYueShu;printf(%d,%d,comYueShu,comBeishu);12.输入一个整数，求它包含又多少个2的因子。（例如，8含有3个2的因子，10含有一个2的因子，15不含有2的因子。）#include stdio.hvoid main()int a=0;int integerGene=0;printf(input a number!n);scanf(%d,&a);while(a%2=0)integerGene+;a/=2; print

10、f(%dn,integerGene);13.计算1！，2！，3！10！#include#define N 10void main() int i; long int a=1; printf(The outcome are:n); for(i=1;i=10;i+) a*=i; printf(The result of %d! is %ldn,i,a); 14.猴子吃桃问题：第一天吃掉总数的一半多一个，第二天又将剩下的桃子吃掉一半多一个，以后每天吃掉前一天剩下的一半多一个，到第十天准备吃的时候见只剩下一个桃子，求第一天开始吃的时候桃子的总数。#include#define N 10void mai

11、n() int i,x10; x9=1; for(i=9;i=1;i-) xi-1=2*(xi+1); printf(The total numbers in the first day are:%dn,x0);15.输入圆锥体的底半径r和高h，计算出圆锥体的体积并输出#include#define PI 3.1415926void main() float r,h,v; printf(Please input the radius and the height:n); scanf(%f%f,&r,&h); v=PI*r*r*h/3; printf(The volume of is %.6fn

12、,v);16题#include stdio.hvoid main() int a,n; long tmp,SUM=0; do printf(nPlease input the number a=); scanf(%d,&a); while(!(a=0 & a=9); printf(nPlease input the number,its value is not too big n=); scanf(%d,&n); tmp = a; while(n-) SUM += tmp; tmp = tmp * 10 + a; printf(na+aa+aaa+.=%ld(a= %d)n,SUM,a);1

13、7题#include stdio.hvoid main()unsigned char week720=Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,saturday; unsigned char weekday;do printf(nPlease input the weeday(0 =the value of weekday = 0 & weekday 1e-6);printf(nThe natural constant e, its %f pow = %f,x,Result);19题#include stdio.h#include math

14、.hvoid main() float a; float x1,x2; printf(nPlease input the number a=); scanf(%f,&a); x1 = x2 = a/2; do x1=x2; x2=(x1+(a/x1)/2; while(fabs(x2 - x1) 1e-5); printf(nInput a namber %f,Its sqrt = %f,a,x2); 第5章课后编程习题参考答案2.已有一个已排好序的数组，现在输入一个数，要求按照原来排序的规则将它插入数组中。#include#define N 7void main() int aN=1,5,1

15、6,45,87,120; int n,i,j,temp1,temp2,end; printf(please enter a number:n); scanf(%d,&n); end=aN-2; if(nend) aN-1=n; else for(i=0;iN-1;i+) if(ni+1;j-) aj=aj-1; ai=n; break; printf(put out the new array:n); for(i=0;iN;i+) printf(%4d,ai);3.打印魔方阵，所谓魔方阵是指这样的方阵，它的每一行，每一列和对角线之和均相等。例如，三阶魔方阵为： 8 1 6 3 5 7 4 9

16、2#includevoid main()int a1616;int n,i,j,k;do printf(enter a number n(115):n); scanf(%d,&n); while(!(n0)&(n=15)&(n%2=1); for(i=1;i=n;i+)for(j=1;j=n;j+)aij=0;j=n/2+1;a1j=1;for(k=2;k=n*n;k+)i=i-1;j=j+1;if(in)i=i+2;j=j-1;elseif(in) j=1;if(aij=0)aij=k;elsei=i+2;j=j-1;aij=k;for(i=1;i=n;i+)for(j=1;j=n;j+)p

17、rintf(%4d,aij); printf(n); 4，有一篇文章，共有3行文字，每行有80个字符，要求分别统计出其中英文大写字母，小写字母，数字，空格以及其它字符的个数。#include#include void main()char s380;int i,j,up,low,num,spa,oth;up=low=num=spa=oth=0;for(i=0;i3;i+)printf(enter the %d line:n,i+1);gets(si);for(j=0;j=A&sij=a&sij=0&sij=9)num+;else if(sij= )spa+;elseoth+;printf(up

18、=%dn,up);printf(low=%dn,low);printf(num=%dn,num);printf(spa=%dn,spa);printf(oth=%dn,oth);5.编写一个程序，将两个字符串连起来，不要用strcat函数。#include#include void main()char s1100,s2100;gets(s1);gets(s2);int i,j;i=j=0;while(s1i!=0)i+;while(s2j!=0)s1i+=s2j+;s1i=0;puts(s1);6.输入每个学生的平均成绩和姓名，将成绩按照递减顺序排序，姓名做相应的调整。输出排序后的成绩和姓名

19、。#include#includedefine N 10/* 假定有十个学生*/void main()char name5010,name110;int markN,i,j,mark1;for(i=0;iN;i+)printf(the %d th students name and mark:n,i+1);scanf(%s%d,namei,&marki); for ( i=0;iN-1;i+) for (j=i+1;jmarki) mark1 = markj; markj = marki; marki = mark1; strcpy(name1,namej); strcpy(namej,nam

20、ei); strcpy(namei,name1); for(i=0;iN;i+) printf(%s,%dn,namei,marki); 7.输出2维数组中行为最大列上为最小的元素（称为鞍点）及其位置。如果不存在任何鞍点，则也应输出相应信息。#includevoid main()int i,j,k,m,n,max,maxj;int a1010;int flag=0;printf(enter the hang number n:n);scanf(%d,&n); printf(enter the lie number m:n); scanf(%d,&m); for(i=0;in;i+)for(j=

21、0;jm;j+)scanf(%d,&aij);printf(n);for(i=0;in;i+) max=ai0; for(j=0;jmax) max=aij; maxj=j; for(k=0;kakmaxj) break; if(k=n)printf(nthe %d hang,the %d lie ,the number %d is an dian!n,i, maxj,max);flag=1;if(!flag)printf(no an dian!);8.计算矩阵A 的转置矩阵A ,例如：A= , A = #includevoid main()int a43,b34;int i,j;printf

22、(enter array a:n);for(i=0;i4;i+)for(j=0;j3;j+)scanf(%d,&aij);for(i=0;i4;i+)for(j=0;j3;j+)printf(%4d,aij);printf(n); for(i=0;i4;i+)for(j=0;j3;j+)bji=aij;for(i=0;i3;i+)for(j=0;j4;j+)printf(%4d,bij);printf(n);9. 输入一个八进制数的字符串，将他转换成等价的十进制字符串，用printf的s格式输出转换结果以检验转换的正确性。例如：输入字符串1732，转换成十进制数的字符串为986。#includ

23、e stdio.h#include string.h#include math.h#define MAX 20void main()int i,len,tmp;long int sum = 0;char inputMAX;char outputMAX=;scanf(%s,input);len = strlen(input);for(i = 0;i len;i +) sum=sum*8+(inputi - 48);for(i = 0;i MAX;i +)outputi = (char)(sum % 10 +48);sum /= 10;if(sum=0)break;len = strlen(out

24、put);for(i = 0;i len/2;i +)tmp = outputi;outputi = outputlen-1;outputlen-1 = tmp;printf(%s,output);10. 输入一行字母串，统计其中各个字母和空格的分别出现的次数。#includevoid main()char s80;int i,up,low,spa;up=low=spa=0;gets(s);for(i=0;si!=0;i+)if(si=A)&(si=a)&(si=z)low+;else if(si= )spa+;else ;printf(the up=%d,the low=%d,the spa

25、=%d,up,low,spa);第6章编程题参考答案 1编写程序,实现:利用指向字符数组的指针变量,统计两个字符数组中相同的字符个数.#include#includevoid main()char s180,s280;char *p1,*p2;int n=0,len1,len2,i,j;p1=s1,p2=s2;gets(s1);gets(s2);len1=strlen(s1);len2=strlen(s2);for(i=0;ilen1&ilen2;i+)if(*(p1+i)=*(p2+i) n+;printf(%d,n);2输入三个整数,按从小到大的顺序输出, 用三种不同方式实现.方法1：#

26、include # include void main() int a3,i,j,temp;/*清屏指令*/ clrscr(); printf(nnPlease input 3 integers :nn); for (i=0;i3;i+) scanf(%d,&ai); for(i=0;i2;i+) for (j=i+1;j3;j+) if (ajai) temp=ai; ai=aj; aj=temp; printf(nnAfter sorted, the 3 inegers:nn); for (i=0;i3;i+) printf(%dt,ai); 方法2：# include # include

27、 void main() int a3,i,j,temp; clrscr(); printf(nnPlease input 3 integers :nn); for (i=0;i3;i+) scanf(%d,a+i); for(i=0;i2;i+) for (j=i+1;j3;j+) if (*(a+j)*(a+i) temp=*(a+i); *(a+i)=*(a+j); *(a+j)=temp; printf(nnAfter sorted, the 3 inegers:nn); for (i=0;i3;i+) printf(%dt,*(a+i); 方法3：# include # includ

28、e void main() void swap(int *p1, int *p2); int a,b,c; int *pa=&a,*pb=&b,*pc=&c; clrscr(); printf(nnPlease input 3 integers :nn); scanf(%d,&a); scanf(%d,&b); scanf(%d,&c); if (bc) swap(pb,pc); if (ab) swap(pa,pb); if (bc) swap(pb,pc); printf(nnAfter sorted, the 3 inegers:nn); printf(%dt%dt%dt,a,b,c);

29、 void swap(int *p1, int *p2) int temp; temp=*p1; *p1=*p2; *p2=temp; 3有一字符串，包含n个字符。使用指针，将此字符串从第m个字符开始的全部字符复制成为另一个字符串。# include # include # include # define N1 20# define N2 20void main() char str1N1,str2N2; int m,n,i,j; clrscr(); printf(nnPlease input a string:nn); gets(str1); n=strlen(str1); do prin

30、tf(nnPlease input place m:nn); scanf(%d,&m); while(nm); for (i=m-1,j=0; in; i+,j+) *(str2+j)=*(str1+i); *(str2+j)=0; printf(nnThe new string :nn); printf(%s,str2); 4 输入一个字符串，内有数字和非数字字符，如:a123x456 17960?302tab5876将其中连续的数字作为一个整数，依次存放到一数组a中。例如123放在a0中，456放在a1中统计共有多少个整数，并输出这些数。# include # include # incl

31、ude # include void main() char str60,ch; int i,j,bit,dit,n; long int a20; clrscr(); printf(nnPlease input a string:nn); scanf(%s,str); for (i=0,j=0,a0=0,bit=1,dit=0;istrlen(str) ;i+) if(isdigit(ch=*(str+i) dit=1; aj*=bit; aj+=(ch-48); bit=10; n=j; else if (dit=1) j+; aj=0 ; dit=0; bit=1; printf (nna

32、i :nn) ; for (i=0;i=n;i+) printf(nna%d=%ldn,i,*(a+i); 5 利用数组和指针,将一个4*4的矩阵转置,并输出矩阵中的最大值及其位置# include # include # define N 4void initpm(float * pm, float mtN);void main() void inputm(float mtN); void printm( float mtN); void schmax(float mtN); void tranmtx(float mtN); float mtxNN ; clrscr(); inputm(mt

33、x); printf(nn); printm(mtx); schmax(mtx); tranmtx(mtx); printm(mtx); printf(n); void inputm(float mtN) int i,j; float *pmN; initpm(pm,mt); printf(nnPlease input a 4*4 matrix:nn); for(i=0;i4;i+) for (j=0;j4;j+,pmi+) scanf(%f,pmi); void printm( float mtN) int i,j; float *pmN; initpm(pm,mt); for(i=0;iN

34、;i+) for(j=0;jN;j+,pmi+) printf(%3.2ft,*pmi); printf(n); void schmax(float mtN) int i,j,line ,colum; float *pmN,max; initpm(pm,mt); max=mt00; line=0; colum=0; for (i=0;iN;i+) for(j=0;jN;j+) if (max*(pmi+j) max=*(pmi+j); line=i; colum=j; printf(nnThe max digital in the matrix :%3.2fnn,max); printf(Th

35、e line of the max digital : %d nn,line+1); printf(The colum of the max digital : %d nn,colum+1); void tranmtx(float mtN) int i,j; float *pmN; initpm(pm,mt); for (i=0;iN;i+) for(j=i+1;jN;j+) float temp; temp=*(pmi+j); *(pmi+j)=*(pmj+i); *(pmj+i)=temp; void initpm(float * pm, float mtN) int i; for (i=

36、0;iN;i+) pmi=mti; 6利用指向指针的指针方法对6个字符串排序并输出.# include # include # include # define N 6void main() char strN20; char *pstrN; int i,j; for (i=0;iN;i+) pstri=stri; char *pp; pp=pstr; clrscr(); printf(nnPlease input %d strings:nn,N); for(i=0;iN;i+) gets(pstri); for(i=0;iN-1;i+) for(j=i+1;j0) char *temp=*(

37、pp+i);*(pp+i)=*(pp+j);*(pp+j)=temp; printf(nnAfter sorted ,the %d strings:nn,N); for(i=0;iN;i+) printf(%sn,*pp+); 7写一程序,求任意一输入字符串的长度,将此输入的字符串按逆序的方式存入所在位置中,显示输入字符串和其逆字符串.# include # include void main() char str80, *pstr=str,ch; int n=0,i; clrscr(); printf(Please input a string:nn); gets(str); printf(

38、nnThe inputing string:nn); printf(%s, str); while(*pstr!=0) pstr+; n+; printf(nnThe length of the string :%d,n); for (i=0;i(n/2); i+) ch=*(str+i); *(str+i)=*(str+n-1-i); *(str+n-1-i)=ch; printf(nnAfter changed ,the string:nn); printf(%snn, str); 8编写一个程序,先读入一段正文,然后删除其中的单词from、in、at、an和on,最后显示该结果文本段.#

39、 include # include # include void delWords(int *pi,int *pN,char *pt);void main() char text10020,*ptext100; int i,N,*pN=&N,*pi=&i; for (i=0;i100;i+) ptexti=texti; clrscr(); printf(Attention : After you input the end of text, please input wordEOF!nn); printf(Please input a text(words=100),EOF end:nn);

40、 for(i=0;strcmp(ptextN,EOF);i+) scanf(%s,ptexti); N=i; for (i=0;i=(N-1);i+) if (strcmp(ptexti,from)=0) delWords(pi,pN,ptext); else if (strcmp(ptexti,in)=0) delWords(pi,pN,ptext); else if (strcmp(ptexti,at)=0) delWords(pi,pN,ptext); else if (strcmp(ptexti,an)=0)delWords(pi,pN,ptext);else if (strcmp(ptexti,on)=0)delWords(pi,pN,ptext); printf(nAfter deleting the words:from ,in at, an, on , the text:nn); for (i=0; i=(N-1);i+) printf(%s ,ptexti); printf(nn); void delWords(int *