期末考试补充测验

期末考试补充测验1.Sum of even numbers2DescriptionGiven a number N(even or odd),calculate 2+4+.+n(n is the largest even number smaller than N).Print out the sum.Input The first line is an integer m,indicating the number of test cases.Then follow m lines.The i line contains a positive number N_i.OutputFor each number N_i,print the sum of 2+4+.+n_i(n_i is the largest even number smaller than N_i)in a single line.Sample Input 258Sample Output 6201.Sum of even numbers3#include using namespace std;int main()int count,num,sum;cincount;for(int i=0;inum;sum=0;for(int j=2;j=num;j+=2)sum+=j;coutsumendl;2.Grade Record Management4DescriptionThere are some students grade records,in format of“name grade”.In order to ease the view and management of the records easily,you are asked to develop a program to print out the records according to the grades.That is,the names are printed in the order of grades.InputTotally,there are 8 records and each record occupies a line.Only letters and digits appear in the name of a student(i.e.there will be no space in a name).Each name contains at most 20 letters or(and)digits.All grades are integers in the range of 0100.OutputEach grade per line,followed by the students having this grade.For students having the same grade,they are listed in the same line,with the same order as in the input.Hints:You can use two arrays to store the names and grades.Sample Input WangYi 90LiMing 90HuRui 50ZhangLi 65LiLei 80ZhangFei 65ZhaoSan 70ChenZi 100Sample Output100 ChenZi90 WangYi LiMing80 LiLei70 ZhaoSan65 ZhangLi ZhangFei50 HuRui2.Grade Record Management5#define SIZE 8#define LEN 25int main()char nameSIZELEN;int gradeSIZE;for(int i=0;i namei;cin gradei;/rankfor(int i=SIZE-1;i 0;-i)for(int j=0;j i;+j)if(gradej gradej+1)char tmpLEN;strcpy(tmp,namej);strcpy(namej,namej+1);strcpy(namej+1,tmp);int tmp2=gradej;gradej=gradej+1;gradej+1=tmp2;/printfor(int i=0;i SIZE;+i)if(i=0|gradei gradei-1)cout gradei;cout gradei+1)cout salpcnttarget;while(sal0)yr=1;sum=12*sal;while(sumtarget)sal+=(sal*pcnt)/100;sum+=12*sal;yr+;coutyrsalpcnttarget;2.String Reversion 9DescriptionGiven a valid identifier in C programs,please write a program to reverse it by respectively reversing two parts separated by _.Input The first line is an integer m,indicating the number of test cases.Then there are m lines and each line contains a string.A string will contain no more than 100 characters and there is one or less _.OutputFor each test case,print out the string reversed.Sample Input 2John_Smithint_45_meSample Output nhoJ_htimStni_54_emString Reversion 10void reversePart(char,int,int);/reverse part of the stringint main()int count;cincount;for(int x=0;xstr;for(int i=0;istrlen(str);i+)if(stri=_)mark=i;break;reversePart(str,0,mark-1);reversePart(str,mark+1,strlen(str)-1);coutstrhigh)return;for(int i=low;ich;while(ch!=#)/Initialze vairalbe for each line of input for(int i=0;i-1&countlast0ch;if(countdigit0countdigit1)countdigit0=countdigit1;/Sort the numbers int max,tmp1,tmp2;/Set the second column to be digits 0.9;for(int i=0;i=9;i+)counti1=i;for(int i=0;i=9;i+)max=findMax(count,i);tmp1=counti0;tmp2=counti1;counti0=countmax0;counti1=countmax1;countmax0=tmp1;countmax1=tmp2;/Print out the results for(int i=0;i0)coutcounti1(counti0);if(i0)cout,;else coutch;int findMax(int count2,int low)int max=low;for(int i=low+1;icountmax0)max=i;else if(counti0=countmax0&counti1countmax1)max=i;return max;4.Change to upper case 13Description Given a line contains multiple words,change the first character in each word to upper case.Input A line containing multiple words.The line contains less than 100 characters.Output The same line with the first character of each word being upper case.Sample Input Please change me to upper-case.Sample Output Please Change Me To Upper-case.Change to upper case14int length(char*string1)for(int i=0;+i)if(string1i=0)return I;char toUpperCase(char c)if(c=a&c=z)return(char)(c-(a-A);return c;void toUpperCase(char*string1,char*string2)int length1=length(string1);int times=0;int status=1;for(int i=0;i length1;+i)if(string1i=)string2i=string1i;status=1;else if(status=1)string2i=toUpperCase(string1i);else string2i=string1i;status=0;int main()char string1100;char string2100;cin.getline(string1,100);toUpperCase(string1,string2);cout string2;5.Cycling the words 15Description Given a line contains N words,print the N lines.The first line is the same as the input.After printing each line,the first word of this line in put to the end of the next line.Input A line contains N words.N is not given in the problem:you need to count the number of words in the input line to find it out.The line contains less than 100 characters.OutputN lines.The first line equals the input.For the rest N-1 lines,the first word in a line in put to the end in the next line.Sample Input Please think about it carefullySample Output Please think about it carefullythink about it carefully Pleaseabout it carefully Please thinkit carefully Please think aboutcarefully Please think about itCycling the words16int length(char*string1)for(int i=0;+i)if(string1i=0)return i;int split(char*string1,char*string2)int length1=length(string1);int count=1;for(int i=0;i length1;+i)string2i=string1i;if(string1i=)+count;string2i=0;return count;void print(char*string1)int length1=length(string1);int words=split(string1,string1);int start=0;for(int i=0;i words;+i)int start2=start;for(int j=i;j words;+j)cout (string1+start2);start2+=length(string1+start2)+1;start2=0;for(int j=0;j i;+j)cout (string1+start2);start2+=length(string1+start2)+1;cout endl;start+=length(string1+start)+1;int main()char string1100;cin.getline(string1,100);print(string1);