C补强阶段作业

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1、编写一个函数。函数的三个参数是一个字符和两个整数。字符参数是需要输出的字符。第1个整数说明了在每行中该字符输出的个数，而第二个整数指的是需要输出的行数。编写一个调用该函数的程序。要求：输入字符为回车时，作为未输入字符处理；输入行列值时若不是数字，直接结束程序。编程考点：循环基本语法；break和continue#include <stdio.h>void chLineRow(char ch, int c, int r);int main(void) char ch;int col, row;printf("Enter a character (# to quit): &q

2、uot;);while ( (ch = getchar() != '#') if (ch = 'n')continue;printf("Enter number of columns and number of rows: ");if (scanf("%d %d", &col, &row) != 2)break;chLineRow(ch, col, row);printf("nEnter next character (# to quit): ");printf("Bye!n&

3、quot;);return 0;void chLineRow(char ch, int c, int r) int col, row;for (row = 0; row < r; row+) for (col = 0; col < c; col+)putchar(ch);putchar('n');return;编写一个函数计算double类型数的某个整数次幂（不得调用系统的函数pow）， 注意0的任何次幂和任何数值的0次幂以及负数次幂并编写测试程序编程考点：if-else的嵌套#include <stdio.h>double power(double a

4、, int b); /* ANSI prototype */int main(void) double x, xpow;int n;printf("Enter a number and the integer power");printf(" to whichnthe number will be raised. Enter q");printf(" to quit.n");while (scanf("%lf%d", &x, &n) = 2) xpow = power(x, n); /* funct

5、ion call */printf("%.3g to the power %d is %.5gn", x, n, xpow);printf("Enter next pair of numbers or q to quit.n");printf("Hope you enjoyed this power trip - bye!n");return 0;double power(double a, int b) /* function definition */double pow = 1;int i;if (b = 0) /if (a =

6、 0)/printf("0 to the 0 undefined; using 1 as the valuen");pow = 1.0; else if (a = 0)pow = 0.0;else if (b > 0)for (i = 1; i <= b; i+)pow *= a;else/* b < 0 */pow = 1.0 / power(a, -b);return pow; /* return the value of pow */写一个计算降水量的程序，给定一个数组，记录的每年每月的降水量const float rainYRSMONTHS = 1

7、0.2, 8.1, 6.8, 4.2, 2.1, 1.8, 0.2, 0.3, 1.1, 2.3, 6.1, 7.4, 9.2, 9.8, 4.4, 3.3, 2.2, 0.8, 0.4, 0.0, 0.6, 1.7, 4.3, 5.2, 6.6, 5.5, 3.8, 2.8, 1.6, 0.2, 0.0, 0.0, 0.0, 1.3, 2.6, 4.2, 4.3, 4.3, 4.3, 3.0, 2.0, 1.0, 0.2, 0.2, 0.4, 2.4, 3.5, 6.6, 8.5, 8.2, 1.2, 1.6, 2.4, 0.0, 5.2, 0.9, 0.3, 0.9, 1.4, 7.2 ;

8、使用指针而不是使用下标进行计算，每年的降水总值、每年平均值，以及每月平均量编程考点：如何用指针定位二维数组的元素#include <stdio.h>#define MONTHS 12 /* number of months in a year */#define YRS 5 /* number of years of data */int main(void) /* initializing rainfall data for 1990 - 1994 */const float rain512 = 10.2, 8.1, 6.8, 4.2, 2.1, 1.8, 0.2,0.3, 1.

9、1, 2.3, 6.1, 7.4 , 9.2, 9.8, 4.4, 3.3, 2.2, 0.8, 0.4,0.0, 0.6, 1.7, 4.3, 5.2 , 6.6, 5.5, 3.8, 2.8, 1.6, 0.2, 0.0,0.0, 0.0, 1.3, 2.6, 4.2 , 4.3, 4.3, 4.3, 3.0, 2.0, 1.0, 0.2,0.2, 0.4, 2.4, 3.5, 6.6 , 8.5, 8.2, 1.2, 1.6, 2.4, 0.0, 5.2,0.9, 0.3, 0.9, 1.4, 7.2 ;int year, month;float subtot, total;printf

10、(" YEAR RAINFALL (inches)n");for (year = 0, total = 0; year < YRS; year+) /* for each year, sum rainfall for each month */for (month = 0, subtot = 0; month < MONTHS; month+)subtot += *(*(rain + year) + month);printf("%5d %15.1fn", 1990 + year, subtot);total += subtot; /* to

11、tal for all years */printf("nThe yearly average is %.1f inches.nn", total/YRS);printf("MONTHLY AVERAGES:nn");printf(" Jan Feb Mar Apr May Jun Jul Aug Sep Oct ");printf(" Nov Decn");for (month = 0; month < MONTHS; month+) /* for each month, sum rainfall over

12、 years */for (year = 0, subtot =0; year < YRS; year+)subtot += *(*(rain + year) + month);printf("%4.1f ", subtot/YRS);printf("n");return 0;编写一个程序，提示用户输入3个数据集，每个数据集包括5个double值。程序应当实现下列所有功能：A 把输入信息存储到一个3*5的数组中B 计算出每个数集(包含5个值)的平均值C 计算所有数值的平均数D 找出这15个数中的最大值打印出结果每个任务需要用一个单独的函数来实现。对

13、于任务B需要编写计算并返回一维数组平均值的函数，循环三次调用该函数来实现任务B。对于任务C、D，函数应当把整个数组做为参数，并却完成任务B、C和D的函数应该向他的调用函数返回答案(推荐使用变长数组，参考程序为变长数组实现)编程考点：循环和二维数组的熟练应用，以及数组作为参数的传递#include <stdio.h>#define ROWS 3#define COLS 5 void store(double ar, int n);double average2d(int rows, int cols, double arrowscols);double max2d(int rows,

14、 int cols, double arrowscols);void showarr2(int rows, int cols, double arrowscols);double average(const double ar, int n);int main(void) double stuffROWSCOLS;int row;for (row = 0; row < ROWS; row+) printf("Enter %d numbers for row %dn", COLS, row + 1);store(stuffrow, COLS);printf("

15、array contents:n");showarr2(ROWS, COLS, stuff);for (row = 0; row < ROWS; row+)printf("average value of row %d = %gn", row + 1, average(stuffrow,COLS);printf("average value of all rows = %gn", average2d(ROWS, COLS, stuff);printf("largest value = %gn", max2d(ROWS,

16、 COLS, stuff);printf("Bye!n");return 0;void store(double ar, int n) int i;for (i = 0; i < n; i+) printf("Enter value #%d: ", i + 1);scanf("%lf", &ari);double average2d(int rows, int cols, double arrowscols) int r, c;double sum = 0.0;for (r = 0; r < rows; r+)fo

17、r (c = 0; c < cols; c+)sum += arrc;if (rows * cols > 0)return sum / (rows * cols);elsereturn 0.0;double max2d(int rows, int cols, double arrowscols) int r, c;double max = ar00;for (r = 0; r < rows; r+)for (c = 0; c < cols; c+)if (max < arrc)max = arrc;return max;void showarr2(int rows

18、, int cols, double arrowscols) int row, col;for (row = 0; row < rows; row+) for (col = 0; col < cols; col+)printf("%g ", arrowcol);putchar('n');double average(const double ar, int n) int i;double sum = 0.0;for (i = 0; i < n; i+)sum += ari;if (n > 0)return sum / n;elsere

19、turn 0.0;编写产生100个1-10的随机数的程序，并以降序排列rand()为C的标准随机数产生函数编程考点：一维数组实现选择排序，嵌套循环的基本使用#include <stdio.h>#include <stdlib.h>void print(const int array, int limit);void sort(int array, int limit);#define SIZE 100int main(void) int i;int arrSIZE;for (i = 0; i < SIZE; i+)arri = rand() % 10 + 1;pu

20、ts("initial array");print(arr, SIZE);sort(arr, SIZE);puts("nsorted array");print(arr, SIZE);return 0;/* sort.c - sorts an integer array in decreasing order */void sort(int array, int limit) int top, search, temp;for (top = 0; top < limit -1; top+)for (search = top + 1; search

21、< limit; search+)if (arraysearch > arraytop) temp = arraysearch;arraysearch = arraytop;arraytop = temp;/* print.c - prints an array */void print(const int array, int limit) int index;for (index = 0; index < limit; index+) printf("%2d ", arrayindex);if (index % 10 = 9)putchar('

22、n');if (index % 10 != 0)putchar('n');设计一个简单的结构用来存储 月份的全称、缩写、月号(1-12)、天数写一个简单的程序 输出从一月开始到用户选择的月份的总天数(2月假设28天)注意，用户输入不区分大小写编程考点：C库字符及字符串函数的初步使用；结构的初步使用#include <stdio.h>#include <string.h>#include <ctype.h>struct month char name10;char abbrev4;int days;int monumb;const st

23、ruct month months12 = "January", "Jan", 31, 1 , "February","Feb", 28, 2 , "March", "Mar", 31, 3 , "April", "Apr", 30, 4 , "May", "May", 31, 5 , "June", "Jun", 30, 6 , "July&qu

24、ot;, "Jul", 31, 7 , "August", "Aug", 31, 8 , "September","Sep", 30, 9 , "October", "Oct", 31, 10 , "November","Nov", 30, 11 , "December", "Dec", 31, 12 ;int days(char * m);int main(void) cha

25、r input20;int daytotal;printf("Enter the name of a month: ");while (gets(input) != NULL && input0 != '0') daytotal = days(input);if (daytotal > 0)printf("There are %d days through %s.n", daytotal, input);elseprintf("%s is not valid input.n", input);pr

26、intf("Next month (empty line to quit): ");puts("bye");return 0;int days(char * m) int total = 0;int mon_num = 0;int i;if (m0 = '0')total = -1;else m0 = toupper(m0);for (i = 1; mi != '0' i+)mi = tolower(mi);for (i = 0; i < 12; i+)if (strcmp(m, monthsi.name) = 0)

27、 mon_num = monthsi.monumb;break;if (mon_num = 0)total = -1;elsefor (i = 0; i < mon_num; i+)total +=monthsi.days;return total;修改下面的代码使他首先按照输入的顺序输出图书的信息，然后按照书名的字母升序输出图书的信息，就后按照value的值升序输出图书的信息，排序的工作由子函数完成。注意，移动数据量很大的单元来实现数组的排序，不可取。可采用辅助的指针数组来实现编程考点：指针数组；结构成员的两种引用方法（-> .）#include <stdio.h>#

28、define MAXTITL 40#define MAXAUTL 40#define MAXBKS 100 /* maximum number of books */struct book /* set up book template */ char titleMAXTITL; char authorMAXAUTL; float value;int main(void) struct book libraryMAXBKS; /* array of book structures */ int count = 0; int index; printf("Please enter th

29、e book title.n"); printf("Press enter at the start of a line to stop.n"); while (count < MAXBKS && gets(librarycount.title) != NULL && librarycount.title0 != '0') printf("Now enter the author.n"); gets(librarycount.author); printf("Now enter t

30、he value.n"); scanf("%f", &librarycount+.value); while (getchar() != 'n') continue; /* clear input line */ if (count < MAXBKS) printf("Enter the next title.n"); if (count > 0) printf("Here is the list of your books:n"); for (index = 0; index <

31、count; index+) printf("%s by %s: $%.2fn", libraryindex.title, libraryindex.author, libraryindex.value); else printf("No books? Too bad.n"); return 0;参考答案代码#include <stdio.h>#include <string.h>#define MAXTITL 40#define MAXAUTL 40#define MAXBKS 100 /* maximum number of

32、books */struct book /* set up book template */char titleMAXTITL;char authorMAXAUTL;float value;void sortt(struct book * pb, int n);void sortv(struct book * pb, int n);int main(void) struct book libraryMAXBKS; /* array of book structures */struct book * pbkMAXBKS; /* pointers for sorting */int count

33、= 0;int index;printf("Please enter the book title.n");printf("Press enter at the start of a line to stop.n");while (count < MAXBKS && gets(librarycount.title) != NULL&& librarycount.title0 != '0') printf("Now enter the author.n");gets(libraryc

34、ount.author);printf("Now enter the value.n");scanf("%f", &librarycount.value);pbkcount = &librarycount;count+;while (getchar() != 'n')continue; /* clear input line */if (count < MAXBKS)printf("Enter the next title.n");printf("Here is the list of

35、your books:n");for (index = 0; index < count; index+)printf("%s by %s: $%.2fn", libraryindex.title,libraryindex.author, libraryindex.value);printf("Here is the list of your books sorted by title:n");sortt(pbk, count);for (index = 0; index < count; index+)printf("%

36、s by %s: $%.2fn", pbkindex->title, pbkindex->author,pbkindex->value);sortv(pbk, count);printf("Here is the list of your books sorted by value:n");for (index = 0; index < count; index+)printf("%s by %s: $%.2fn", pbkindex->title, pbkindex->author,pbkindex->

37、;value);return 0;void sortt(struct book * pb, int n) int top, search;struct book * temp;for (top = 0; top < n -1; top+)for (search = top + 1; search < n; search+)if (strcmp(pbsearch->title, pbtop->title) < 0) temp = pbsearch;pbsearch = pbtop;pbtop = temp;void sortv(struct book * pb, i

38、nt n) int top, search;struct book * temp;for (top = 0; top < n -1; top+)for (search = top + 1; search < n; search+)if (pbsearch->value < pbtop->value) temp = pbsearch;pbsearch = pbtop;pbtop = temp;编写程序满足下列要求a) 定义一个name结构，它含有两个成员：一个字符串用于存放名字，另一个字符串用于存放姓氏b) 定义一个student结构，它含有3个成员：name结构，

39、一个存放3个浮点数的grade数组，以及一个存放这3个数平均值的变量c) 使用main()函数声明一个具有CSIZE(CSIZE=4)个student结构的数组，用来作为一个班级的数组，并随意初始化这些结构的名字部分，即：初始化一个班级数组里面学生的姓名。使用函数来执行d,e,f,g所描述的任务d) 请求输入学生的分数，以交互地获取每个学生的成绩。将分数放到相应结构的grade数组成员中。可以自主选择在main()或一个函数中实现这个循环e) 为每个结构计算平均分，并把平均值赋给合适的成员f) 输出每个结构的信息g) 输出每门课程的班级平均分编程考点：结构数组的使用#include <s

40、tdio.h>#include <string.h>#define LEN 14#define CSIZE 4#define SCORES 3struct name char firstLEN;char lastLEN;struct student struct name person;float scoresSCORES;float mean;void get_scores(struct student ar, int lim);void find_means(struct student ar, int lim);void show_class(const struct

41、student ar, int lim);void show_ave(const struct student ar, int lim);int main(void) struct student classCSIZE = "Flip", "Snide" , "Clare", "Voyans" , "Bingo", "Higgs" , "Fawn", "Hunter" ;get_scores(class, CSIZE);find_mea

42、ns(class, CSIZE);show_class(class, CSIZE);show_ave(class, CSIZE);return 0;void get_scores(struct student ar, int lim) int i, j;for (i = 0; i < lim; i+) printf("Please enter %d scores for %s %s:n", SCORES,ari.person.first, ari.person.last);for (j = 0; j < SCORES; j+) while (scanf(&quo

43、t;%f", &ari.scoresj) != 1) scanf("%*s");puts("Please use numeric input.");void find_means(struct student ar, int lim) int i, j;float sum;for (i = 0; i < lim; i+) for (sum = 0, j = 0; j < SCORES; j+)sum += ari.scoresj;ari.mean = sum / SCORES;void show_class(const st

44、ruct student ar, int lim) int i, j;char wholename2*LEN;for (i = 0; i < lim; i+) strcpy(wholename, ari.person.first);strcat(wholename, " ");strcat(wholename, ari.person.last);printf("%27s: ", wholename);for (j = 0; j < SCORES; j+)printf("%6.1f ", ari.scoresj);print

45、f(" Average = %5.2fn", ari.mean);void show_ave(const struct student ar, int lim) int i, j;float total;printf("n%27s: ", "QUIZ AVERAGES");for (j = 0; j < SCORES; j+) for (total = 0, i = 0; i < lim; i+)total += ari.scoresj;printf("%6.2f ", total / lim);put

46、char('n');编写一个程序，用指向函数的指针数组执行菜单功能（程序中不得使用if-else语句和switch-case语句）。例如实现如下菜单编程考点：函数指针和函数指针数组#include <stdio.h>#include <math.h>double twice(double x);double half(double x);double thrice(double x);void showmenu(void);#define NUM 4int main(void) double (*pfNUM)(double) = twice, half,

47、 thrice, sqrt ;double val;double ans;int sel;printf("Enter a number (negative to quit): ");while (scanf("%lf", &val) && val >= 0) showmenu();while (scanf("%d", &sel) && sel >= 0 && sel <= 3) ans = (*pfsel)(val);printf("answe

48、r = %fn", ans);showmenu();printf("Enter next number (negative to quit): ");puts("bye");return 0;void showmenu(void) puts("Enter one of the following choices:");puts("0) double the value 1) halve the value");puts("2) triple the value 3) squareroot the value");puts("4) next number");double twice(double x) return 2.0 * x;double half(double x) return x / 2.0;double thrice(double x) return 3.0 * x;