梁柱屈曲分析荷载位
abaqus 分析梁柱屈曲问题，如何查看其荷载 位移曲线？Sectio里面分析的几个例子如l本人是 ABAQUS 新手，最近学习 ABAQUS Benchmarks Manual 里的 “Buckling analysis,” 梁、圆柱壳等都有大量的 INP 文件。其中 beambuckle_b31os_load_isec.inp 如下。*HEADINGLATERAL BUCKLING: B31OS, *BEAM SECTION, SECTION=I*NODE1, 0.0000E+00, 0.0000E+00, 0.0, 0.0000E+00, 0.0000E+00,-1.02, 6.0000E-01,-2.4222E-04, 0.0, 9.1382E-08, 4.5345E-04,-1.03, 1.2000E+00,-4.8288E-04, 0.0, 1.7867E-07, 8.9808E-04,-1.04, 1.8000E+00,-7.1826E-04, 0.0, 2.5496E-07, 1.3247E-03,-1.05, 2.4000E+00,-9.4284E-04, 0.0, 3.1164E-07, 1.7237E-03,-1.06, 3.0000E+00,-1.1500E-03, 0.0, 3.4040E-07, 2.0850E-03,-1.07, 3.6000E+00,-1.3324E-03, 0.0, 3.3503E-07, 2.3984E-03,-1.08, 4.2000E+00,-1.4830E-03, 0.0, 2.9322E-07, 2.6543E-03,-1.09, 4.8000E+00,-1.5957E-03, 0.0, 2.1761E-07, 2.8439E-03,-1.010, 5.4000E+00,-1.6654E-03, 0.0, 1.1591E-07, 2.9606E-03,-1.011, 6.0000E+00,-1.6889E-03, 0.0, 0.0000E+00, 3.0000E-03,-1.012, 6.6000E+00,-1.6654E-03, 0.0,-1.1591E-07, 2.9606E-03,-1.013, 7.2000E+00,-1.5957E-03, 0.0,-2.1761E-07, 2.8439E-03,-1.014, 7.8000E+00,-1.4830E-03, 0.0,-2.9322E-07, 2.6543E-03,-1.015, 8.4000E+00,-1.3324E-03, 0.0,-3.3503E-07, 2.3984E-03,-1.016, 9.0000E+00,-1.1500E-03, 0.0,-3.4040E-07, 2.0850E-03,-1.017, 9.6000E+00,-9.4284E-04, 0.0,-3.1164E-07, 1.7237E-03,-1.018, 1.0200E+01,-7.1826E-04, 0.0,-2.5496E-07, 1.3247E-03,-1.019, 1.0800E+01,-4.8288E-04, 0.0,-1.7867E-07, 8.9808E-04,-1.020, 1.1400E+01,-2.4222E-04, 0.0,-9.1382E-08, 4.5345E-04,-1.021, 1.2000E+01, 0.0000E+00, 0.0, 0.0000E+00, 0.0000E+00,-1.0 *ELEMENT,TYPE=B31OS1,1,2*ELGEN,ELSET=BEAM1,20,1,1*BEAM SECTION,SECTION=I,ELSET=BEAM,MATERIAL=MAT0.345,0.69, 0.3,0.3, 0.027,0.027, 0.01450.0,-1.0,0.0*MATERIAL,NAME=MAT*ELASTIC2.1E11,0.3125*BOUNDARY1,1,421,2,4.025, 1., 1.E-4, , ,11,3,-0.3*DLOADBEAM, PZ, -100000.,*MONITOR,NODE=11,DOF=3*EL PRINT,FREQUENCY=20*NODE PRINT,FREQUENCY=5COORD,U,RF ,*NSET,NSET=NOUT,GENERATE2,20*NODE FILE,NSET=NOUTU,*EL FILE,FREQUENCY=25S,ESF,*CONTROLS,PARAMETERS=FIELD,0.0,*END STEP首先，不清楚为何一个节点的坐标有6 个？还有 “*STEP,NLGEOM,INC=50*STATIC,RIKS.025, 1., 1.E-4, , ,11,3,-0.3*DLOADBEAM, PZ, -100000.,*MONITOR,NODE=11,DOF=3*EL PRINT,FREQUENCY=20*NODE PRINT,FREQUENCY=5" 段很多地方都不懂，不知哪位好心人能帮助解释一下？先谢谢了！还有计算分析后如何得到如ABAQUS Benchmarks ManuaI中的Figure 1.2.1的荷载-位移曲线？ Figure 1.2.1liyan_5555512助理工程师abaqus分析梁柱屈曲问题，如何査看其荷载位移曲线?本人是 ABAQUS 新手，最近学习 ABAQUS Benchmarks Manua I 里的 “Buckling analysis,” Sec tio 里 面分析的几个例子如I梁、圆柱壳等都有大量的INP文件。其中beambuckle_b31os_load_isec.inp如下。 *HEADING精华0积分66帖子33水位66技术分0LATERAL BUCKLING: B31OS, *BEAM SECTION, SECTION = I*NODE1, 0.0000E+00, 0.0000E+00, 0.0, 0.0000E+00, 0.0000E+00,-1.02, 6.0000E-01,-2.4222E-04, 0.0, 9.1382E-08, 4.5345E-04,-1.03, 1.2000E+00,-4.8288E-04, 0.0, 1.7867E-07, 8.9808E-04,-1.04, 1.8000E+00,-7.1826E-04, 0.0, 2.5496E-07, 1.3247E-03,-1.05, 2.4000E+00,-9.4284E-04, 0.0, 3.1164E-07, 1.7237E-03,-1.06, 3.0000E+00,-1.1500E-03, 0.0, 3.4040E-07, 2.0850E-03,-1.07, 3.6000E+00,-1.3324E-03, 0.0, 3.3503E-07, 2.3984E-03,-1.08, 4.2000E+00,-1.4830E-03, 0.0, 2.9322E-07, 2.6543E-03,-1.09, 4.8000E+00,-1.5957E-03, 0.0, 2.1761E-07, 2.8439E-03,-1.010, 5.4000E+00,-1.6654E-03, 0.0, 1.1591E-07, 2.9606E-03,-1.011, 6.0000E+00,-1.6889E-03, 0.0, 0.0000E+00, 3.0000E-03,-1.012, 6.6000E+00,-1.6654E-03, 0.0,-1.1591E-07, 2.9606E-03,-1.013, 7.2000E+00,-1.5957E-03, 0.0,-2.1761E-07, 2.8439E-03,-1.014, 7.8000E+00,-1.4830E-03, 0.0,-2.9322E-07, 2.6543E-03,-1.015, 8.4000E+00,-1.3324E-03, 0.0,-3.3503E-07, 2.3984E-03,-1.016, 9.0000E+00,-1.1500E-03, 0.0,-3.4040E-07, 2.0850E-03,-1.017, 9.6000E+00,-9.4284E-04, 0.0,-3.1164E-07, 1.7237E-03,-1.018, 1.0200E+01,-7.1826E-04, 0.0,-2.5496E-07, 1.3247E-03,-1.019, 1.0800E+01,-4.8288E-04, 0.0,-1.7867E-07, 8.9808E-04,-1.020, 1.1400E+01,-2.4222E-04, 0.0,-9.1382E-08, 4.5345E-04,-1.021, 1.2000E+01, 0.0000E+00, 0.0, 0.0000E+00, 0.0000E+00,-1.0*ELEMENT,TYPE=B31OS1,1,2*ELGEN,ELSET=BEAM1,20,1,1*BEAM SECTION,SECTION = I,ELSET=BEAM,MATERIAL=MAT0.345,0.69, 0.3,0.3, 0.027,0.027, 0.01450.0,-1.0,0.0*MATERIAL,NAME=MAT*ELASTIC2.1E11,0.3125*BOUNDARY1.1.421.2.4*DLOADBEAM, PZ, -100000.,*MONITOR,NODE=11,DOF=3*EL PRINT,FREQUENCY=20*NODE PRINT,FREQUENCY=5COORD,U,RF ,*NSET,NSET=NOUT,GENERATE2,20*NODE FILE,NSET=NOUTU,*EL FILE,FREQUENCY=25S,ESF,*CONTROLS,PARAMETERS=FIELD,0.0,*END STEP首先，不清楚为何一个节点的坐标有6个？还有 “*STEP,NLGEOM,INC=50*STATIC,RIKS.025, 1., 1.E-4, , ,11,3,-0.3*DLOADBEAM, PZ, -100000.,*MONITOR,NODE=11,DOF=3*EL PRINT,FREQUENCY=20*NODE PRINT,FREQUENCY=5" 段很多地方都不懂，不知哪位好心人能帮助解释一下？先谢谢了!还有计算分析后如何得到如ABAQUS Benchmarks ManuaI中的Figure 1.2.1的荷载-位移曲线？Figure 1.2.1MOLISATO助理工程师精华0积分69帖子35水位69技术分0*STEP,NLGEOM,INC=50*考虑大变形NLGEOM，最大增量步数INC=50*STATIC,RIKS*弧长法RIKS分析.025, 1., 1.E-4, , ,11,3,-0.3*初始步长、时间步、最小步长*DLOAD*集中力BEAM, PZ, -100000.,*MONITOR,NODE=11,DOF=3*监视节点11位移，以控制计算停止*EL PRINT,FREQUENCY=20*NODE PRINT,FREQUENCY=5*结果输出控制bchchh助理工程师精华积分帖子水位技术分0inhcz助理工程师zssm6 :最好参阅一下ABAQUS手册，许多问题会迎刃而解。精华0积分68帖子34水位68技术分0等于没说，以后这种话少讲huaze2007助理工程师精华0积分80帖子38水位80技术分0*STATIC,RIKS.025, 1., 1.E-4, , ,11,3,-0.3前面参数的含义我明白了，但是为什么会有后面几个参数?/ / ,11,3,-0.3请详细解释！梧桐雨助理工程师没记错的话应该是计算中的位移控制量:N0DE11的U3达到-0.3时停止计算。精华0积分81帖子38水位81技术分0jiali助理工程师monitor u3方向位移时，当u3达到-0.3停止，那么是不收敛了还是收敛但最多计算到这样大的变形呢精华0积分47帖子23水位47技术分0
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