c++程序设计谭浩强课后习题答案

《c++程序设计谭浩强课后习题答案》由会员分享，可在线阅读，更多相关《c++程序设计谭浩强课后习题答案（20页珍藏版）》请在装配图网上搜索。

1、第一章1.5题#includeusingnamespacestd;intmain()cout,This,is,;cout,a,C+H;cout,program.M;return0;1.6题includeusingnamespacestd;intmain()inta,b,c;a=10;b=23;c=a+b;cout,a+b=;coutc;coutendl;return0;1.7七题#includeusingnamespacestd;intmain()intabc;intf(intx,intyjntz);cinabc;c=f(a,b,c);coutcendl;return0;intf(intxjn

2、ty,intz)intm;if(xy)m=x;elsem=y;if(zm)m=z;return(m);1.8题/includeusingnamespacestd;intmain()intabc;cinab;c=a+b;cout,a+b=,a+bendl;return0;1.9题/includeusingnamespacestd;intmain()intabc;intadd(intxnty);cinab;c=add(a,b);cout,a+b=,cendl;return0;intadd(intxnty)intz;z=x+y;return(z);2.3题/includeusingnamespace

3、std;intmain()charcl=,a,c2=,b,zc3=,c,/c4=,101,/c5=,116,;coutclc2c3,n,;cout,tb,c4,t,c5,n,;return0;2.4题/includeusingnamespacestd;intmain()charcl=,C,c2=,+/c3=+,;coutHlsay:,clc2c3,H,;cout,tt,Hesays:C+isveryinteresting!,Hreturn0;2.7题includeusingnamespacestd;intmain()inti,j,mzn;i=8；j=10；m=+i+j+;n=(+i)+(+j)

4、+m;couti,t,j,t,m,t,nendl;return0;2.8题includeusingnamespacestd;intmain()charcl=,C,/c2h：c3=,i,c4=,nl/c5=,a;cl+=4;c2+=4;c3+=4;c4+=4;c5+=4;coutHpasswordis:,clc2c3c4c5endl;return0;3.2题includeincludeusingnamespacestd;intmain()floath,r,s，sq,vq/z;constfloatpi=3.1415926;coutHpleaseenterch:;cinrh;l=2*pi*r;s=r

5、*r*pi;sq=4*pi*r*r;vq=3.0/4.0*pi*r*r*r;vz=pi*r*r*h;coutsetiosflags(ios:fixed)setiosflags(ios:right)setprecision(2);coutHl=,setw(10)lendl;coutHs=Hsetw(10)sendl;cout,sq=,setw(10)sqendl;cout,vq=,setw(10)vqendl;cout,vz=,setw(10)vzendl;return0;3.3题/includeusingnamespacestd;intmain()floatczf;cout“请输入一个华氏温度

6、:”；cinf;c=(5.0/9.0)*(f-32);注意5和9要用实型表示，否则5/9值为0cout摄氏温度为:cendl;return0;3.4题/includeusingnamespacestd;intmain()charcl,c2;cout“请输入两个字符cl,c2:“；cl=getchar();将输入的第一个字符赋给clc2=getchar();将输入的第二个字符赋给c2cout用putchar函数输出结果为:；putchar(cl);putchar(c2);coutendl;cout“用cout语句输出结果为:“；coutclc2endl;return0;3.4题另一解/inclu

7、deusingnamespacestd;intmain()charcl,c2;cout“请输入两个字符cl,c2:“；cl=getchar();将输入的第一个字符赋给clc2=getchar();将输入的第二个字符赋给c2cout用putchar函数输出结果为:;putchar(cl);putchar(44);putchar(c2);coutendl;cout“用cout语句输出结果为:“；coutcl,/,c2endl;return0;3.5题/includeusingnamespacestd;intmain()charcl,c2;intil,i2;定义为整型cout-请输入两个整数il,i

8、2:“；cinili2;cl=il;c2=i2;cout按字符输出结果为:,clH,c2endl;return0;3.8题/includeusingnamespacestd;intmain()inta=3/b=4/c=5,x/y;cout(a+bc&b=c)endl;cout(a11b+c&b-c)endl;cout(!(ab)&!c|l)endl;cout(!(x=a)&(y=b)&0)endl;cout(!(a+b)+c-l&b+c/2)endl;return0;3.9题ineludeusingnamespacestd;intmain()inta,b,c;coutpleaseenterth

9、reeintegernumbers:1;cinabc;if(ab)if(bc)cout,max=,c;elsecout,max=,b;elseif(ac)cout,max=,c;elsecout,max=,a;coutendl;return0;3.9题另一解includeusingnamespacestd;intmain()intabc,temp,max;coutpleaseenterthreeintegernumbers:;cinabc;temp=(ab)?a:b;存入temp中*/max=(tempc)?temp:c;者与c比较，最大者存入max*/cout,max=,maxendl;re

10、turn0;3.10题include/*将a和b中的大者/*将a和b中的大usingnamespacestd;intmain()intx,y;coutHenterx:H;cinx;if(xl)y=x;cout,x=,x,/y=x=y;elseif(x10)y=2*x-l;cout,x=x,/y=2*x-l=Hy;elsey=3*x-ll;cout,x=x,/y=3*x-ll=uy;/lWxVIO/xlOcoutendl;return0;3.11 题/includeusingnamespacestd;intmain()floatscore;chargrade;coutHpleaseentersc

11、oreofstudent:;cinscore;while(score100|score0)coutHdataerror,enterdataagain.;cinscore;switch(int(score/10)case10:case9:grade=,A;break;case8:grade=Bf;break;case7:grade=,C,;break;case6:grade=D,;break;default:grade=,E,;coutHscoreis,score,/gradeisHgradeendl;return0;3.12 题/includeusingnamespacestd;intmain

12、()longintnum;intindiytenhundred,thousanctten_thousand,place;/*分别代表个位，十位，百位，千位，万位和位数*/coutHenteraninteger(099999):;cinnum;if(num9999)place=5;elseif(num999)place=4;elseif(num99)place=3;elseif(num9)place=2;elseplace=l;cout,place=,placeendl;计算各位数字ten_thousand=num/10000;thousand=(int)(num-ten_thousand*10

13、000)/1000;hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);coutHonginalorder:;switch(place)case5:coutten_thousandTthousanckvfvvhundreck,/,ten,/,indivendl;coutHre

14、verseorder:1;coutindivtenhundredthousandten_thousandendl;break;case4:coutthousand,/,hundred,/,ten,/,indivendl;coutHreverseorder:1;coutindivtenhundredthousandendl;break;case3:couthundred,/,ten,/,，indivendl;coutHreverseorder:1;coutindivtenhundredendl;break;case2:coutten,/,indivvcendl;coutHreverseorder

15、:1;coutindivtenendl;break;casel:coutindivendl;coutHreverseorder:1;coutindivendl;break;return0;3.13 题includeusingnamespacestd;intmain()longi;/i为利润floatbonus”bonl，bon2,bon4,bon6，bonl0;bonl=100000*0.1;bon2=bonl+100000*0.075;金bon4=bon2+100000*0.05;金bon6=bon4+100000*0.03;金bonl0=bon6+400000*0.015;奖金coutHe

16、nteri:;cini;if(i=100000)bonus=i*0.1;内按10%提成奖金elseif(i=200000)bonus=bonl+(i-100000)*0.075;20万时的奖金elseif(i=400000)bonus=bon2+(i-200000)*0.05;40万时的奖金elseif(i=600000)bonus二bon4+(卜400000)*0.03;60万时的奖金elseif(i=1000000)bonus=bon6+(i-600000)*0.015;利润为10利润为20利润为4利润为60利润为10利润在利润在1利润在2利润在4利润在6100万时的奖金elsebonus

17、=bonl0+(i-1000000)*0.01;/利润在以上时的奖金coutbonus=llbonusendl;万元时的奖金万元时的奖I万元时的奖万元时的奖万元时的10万元以）万元至万元至万元至）万元至）0万元return0;3.13题另一解includeusingnamespacestd;intmain()longi；floatbonus,bonl,bon2,bon4,bon6,bonl0;intc;bonl=100000*0.1;bon2=bonl+100000*0.075;bon4=bon2+200000*0.05;bon6=bon4+200000*0.03;bonl0=bon6+400

18、000*0.015;coutHenteri:;cini;c=i/100000;if(c10)c=10;switch(c)case0:bonus=i*0.1;break;case1:bonus二bonl+(卜100000广0.075;break;case2:case3:bonus=bon2+(i-200000)*0.05;break;case4:case5:bonus=bon4+(i-400000)*0.03;break;case6:case7:case8:case9:bonus=bon6+(i-600000)*0.015;break;case10:bonus=bonl0+(i-1000000)

19、*0.01;coutbonus=bonusendl;return0;3.14 题/includeusingnamespacestd;intmain()inttzazb,c,d;coutHenterfournumbers:;cinabcd;cout,a=,ab)t=a;a=b;b=t;if(ac)t=a;a=c;c=t;if(ad)t=a;a=d;d=t;if(bc)t=b;b=c;c=t;if(bd)t=b;b=d;d=t;if(cd)t=c;c=d;d=t;coutHthesortedsequence:”endl;couta,/,b,/,c,/udendl;return0;3.15 题/in

20、cludeusingnamespacestd;intmain()intpinmtemp;coutNpleaseentertwopositiveintegernumbersnzm:;cinnm;if(nm)temp二n;n=m;m=temp;把大数放在n中，小数放在m中p=n*m;先将n和m的乘积保存在p中，以便求最小公倍数时用while(m!=0)求n和m的最大公约数r=n%m;n=m;m=r;cout,HCF=,lnendl;coutLCD=p/nendl;/p是原來两个整数的乘积return0;3.16 题/includeusingnamespacestd;intmain()charc;i

21、ntletters=0,space=0,digit=0,other=0;coutHenteroneline:Hendl;while(c=getchar()!=,n,)if(c=a&c=A&c=,0,&c=,9,)digit+;elseother+;cout,letter:,letters,/space:,space,/digit:,digit,/other:otherendl;return0;3.17 题/includeusingnamespacestd;intmain()intn=0,tn=0;cout,a/n=:;cinan;while(i=n)tn二tn+a;sn二sn+tn;a=a*1

22、0;+i；赋值后的tn为i个a组成数的值赋值后的sn为多项式前i项之和cout,a+aa+aaa+.=,snendl;return0;3.18 题/includeusingnamespacestd;intmain()floats=0,t=l;intn;for(n=l;n=20;n+)t=t*n;/求n!s=s+t;/将各项累加cout,l!+2!+.+20!=,sendl;return0;3.19 题/includeusingnamespacestd;intmain()intij,k,n;coutHnarcissusnumbersare:Hendl;for(n=100;n1000;n+)i=n

23、/100;j=n/10-i*10;k=n%10;if(n=i*i*i+j*j*j+k*k*k)coutncoutendl;return0;3.20 题/includeusingnamespacestd;intmain()constintm=1000;/定义寻找范围intkbk乙k3,k4，k5，k6,k7，k&k9,kl0;intiza,n,s;for(a=2;a=m;a+)/a是2-1000之间的整数，检査它是否为完数n=0;/n用來累计a的因子的个数s=a;/s用來存放尚未求出的因子之和，开始时等于afor(i=l;il)coutkl,/,，k2;/nl表示a至少有2个因子if(n2)co

24、ut,/,k3;/n2表示至少有3个因子，故应再输出一个因子if(n3)cout,/,，k4;/n3表示至少有4个因子，故应再输出一个因子if(n4)cout,/,，k5;/以下类似if(n5)cout,/,，k6;if(n6)cout,/,k7;if(n7)cout”/k&if(n8)cout,/,k9;if(n9)coutll/,kl0;coutendlendl;return0;3.20题另一解/includeusingnamespacestd;intmain()intm,s,i;for(m=2;m1000;m+)s=0;for(i=l;im;i+)if(m%i)=0)s=s+i;if(s

25、=m)coutmnisa完数endl;coutitsfactorsare:;for(i=l;im;i+)if(m%i=0)couticoutendl;return0;3.20题另一解includeusingnamespacestd;intmain()intkll;intfor(a=2;a=1000;a+)n=0;s=a;for(i=l;ia;i+)if(a%i)=0)n+；s=s-i;kn=i;/将找到的因子赋给klk10if(s=0)coutaisa完数endl;coutitsfactorsare:;for(i=l;in;i+)coutki；coutknendl;return0;3.21 题

26、includeusingnamespacestd;intmain()intiWO;doublea=2,b=l/s=0;for(i=l;i=n;i+)s二s+a/b;t=a;a=a+b;/将前一项分子与分母之和作为卜一项的分子b=t:/将前_项的分子作为下一项的分母cout,sum=,sendl;return0;3.22 题/includeusingnamespacestd;intmain()intday,xlzx2;day=9;x2=l;while(day0)xl=(x2+l)*2;/第1天的桃子数是第2天桃子数加1后的2倍x2=xl;day-;cout,total=,xlendl;retur

27、n0;3.23 题/include#includeusingnamespacestd;intmain()floata,x0,xl;coutHenterapositivenumber:;cina;/输入a的值x0=a/2;xl=(x0+a/x0)/2;dox0=xl;xl=(x0+a/x0)/2;while(fabs(x0-xl)=le-5);coutHThesquarerootofl,aHisxlendl;return0;3.24 题includeusingnamespacestd;intmain()/输出上面4行末号/输出*号输出完一行*号后换行inti,k;for(i=0;i=3;i+)f

28、or(k=0;k=2*i;k+)cout,*H;coutendl;for(i=0;i=2;i+)/输出下面3行审号for(k=O;k=4-2*i;k+)cout,*H;/输出*号coutendl;/输出完一行1*号后换行return0;3.25 题includeusingnamespacestd;intmain()chari,j,k;/*i是a的对手;j是b的对手;k是c的对手*/for(i=,X,;i=,Zl;i+)for(j=,X;j=Z,;j+)if(i!=j)for(k=,X,;k=,Z,;k+)if(i!=k&j!=k)if(i!=X&k!=X&k!=Z)cout,A-,iHB-,j

29、HC-kendl;return0;4.1题includeusingnamespacestd;intmain()inthcf(intjnt);intlcd(int,int,int);intu,vzhj;cinuv;h=hcf(u/v);cout,H.C.F=,hendl;l=lcd(u/v/h);cout,L.C.D=,lendl;return0;inthcf(intu,intv)inttzr;if(vu)t=u;u=v;v=t;while(r=u%v)!=0)u=v;v=r;return(v);intlcd(intujntyinth)(return(u*v/h);4.2题/include#in

30、cludeusingnamespacestd;floatxl/x2/disc,p/q;intmain()voidgreater_than_zero(floatjloat);voidequal_to_zero(float/float);voidsmaller_than_zero(float,float);floata,b,c;coutinputazbzc:;cinabc;disc=b*b-4*a*c;cout,root:,endl;if(disc0)greater_than_zero(a,b);cout,xl=xl,/x2=,x2endl;elseif(disc=0)equal_to_zero(

31、a,b);cout,xl=xl,/x2=,x2endl;elsesmaller_than_zero(a,b);cout,xl=,p,+,q,i,endl;cout,x2=,p,-,q,iendl;return0;/*定义一个函数,定义一个函数，用voidgreater_than_zero(floata,floatb)用来求disc0时方程的根*/(xl=(-b+sqrt(disc)/(2*a);x2=(-b-sqrt(disc)/(2*a);voidequal_to_zero(floatajloatb)來求disc=0时方程的根*/xl=x2=(-b)/(2*a);voidsmaller_th

32、an_zero(floata,floatb)/*定义一个函数,用来求disc0时方程的根*/P=-b/(2*a);q=sqrt(-disc)/(2*a);4.3题/includeusingnamespacestd;intmain()intprime(int);/*函数原型声明*/intn;coutinputaninteger:;cinn;if(prime(n)coutnHisaprime.Hendl;elsecoutnHisnotaprime.Hendl;return0;intprime(intn)intflag=lj;for(i=2;in/2&flag=l;i+)if(n%i=0)flag=

33、0;return(flag);4.4题/includeusingnamespacestd;intmain()intfac(int);inta/b,c/sum=0;coutMenterabc:”；cinabc;sum=sum+fac(a)+fac(b)+fac(c);couta,!+,b,!+,c,!=,sumendl;return0;intfac(intn)intf=l;for(inti=l;i=n;i+)f=f*i;returnf;4.5题/include#includeusingnamespacestd;intmain()doublee(double);doublex,sinh;coutM

34、enterx:;cinx;sinh=(e(x)+e(-x)/2;cout,sinh(,x)=l，sinhendl;return0;doublee(doublex)returnexp(x);4.6题/include#includeusingnamespacestd;intmain()doublesolut(double,double,double,double);doublea,b,c,d;coutinputa,b,c,d:;cinabcd;cout,x=,solut(a,b,c/d)endl;return0;doublesolut(doublea,doublebzdoublec,doubled)doublex=l/xO,f/fl;do